MI vs KXIP – Mumbai win’s by 48 runs!!

IPL 2020 Kxip vs MI Captain Rohit Sharma (Rohit Sharma) then Hardik Pandya and Kieron Pollard’s batting helped Mumbai Indians beat Kings XI Punjab by 48 runs. Mumbai had scored 191 runs in the first innings. In return, Punjab managed to score 143 runs for the loss of 8 wickets in 20 overs.

Mumbai had challenged Punjab for 192 runs. Captain KL Rahul and Mayank Agarwal got off to a good start. But Jaspreet Bumrah will bowl Mayank in the fifth over and Punjab’s innings began to decline. After that, Karunar Pandya will take the wicket of Karun Nair. With Punjab scoring 60, Chahar took Rahul’s wicket and tilted the match in Mumbai’s favor.

After Rahul’s dismissal, Nicholas Puran and Glenn Maxwell helped Punjab win. But the pair did not last long. Puran was dismissed for 44 while Maxwell was dismissed for 11.

Punjab captain KL Rahu won the toss and elected to bowl first. This decision seemed right at first as Mumbai were 21 for two. In the first over, Kortel bowled Decock for zero to give Mumbai the lead. Suryakumar Yadav was then dismissed for a steal. After that, hero Ishan Kishan and skipper Rohit Sharma shared a 62-run stand for the third wicket.

Rohit completes 38th half century in IPL After half a century, he fell on the bowlers. Rohit returned with 70 runs. He scored 70 off 45 balls with eight fours and three sixes. Mumbai had scored 129 for 5 in 17 overs but then Hardik Pandya and Pollard hit fours and sixes. He scored 89 runs in the last 5 overs. As a result, Mumbai reached 191 runs in 20 overs.

For Mumbai, Pollard scored 47 off 20 overs while Hardik scored 30 off 11 balls. Both of them scored 62 runs in the last 3 overs.

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